India has one of largest electrical networks in the world. Different types of sources and load are feeding and consuming power from this massive mesh called the NATIONAL GRID. All the sources are connected in parallel. Parallel operation of the generators improves the reliability of the power system by allowing the isolation of few generators for maintenance or under fault condition without any loss of load.
Maximum percentage of power generation is done by Coal based and hydro-based power plants which use synchronous generators as the generating unit. Wouldn't it be interesting to understand how these power plants control the flow of power and maintain such a large network where there is so much variation of load time to time. Let’s become adept over it.
To begin with lets analyze two synchronous generators working in parallel and observe how various circuit parameters are affected. There are two ways how the generating unit control the power flow to the grid:
- Adjusting the Driving Torque
- Adjusting the Excitation Voltage
In this post we shall discuss just the affect of change of driving torque on various parameters.
Let us consider two alternators connected in parallel and
are unloaded. With respect to external circuit, both the emfs of generators are in
phase and with respect to the local circuit they are in phase opposition.
Driving torque can be varied by controlling the gate
openings of the hydro turbines or by throttle openings of steam turbine. In
this article, we have considered cylindrical rotor generator but the results
are equally relevant to salient pole generator too.
If we increase the driving torque of generator
1, then speed increases and generator 1 emf (Ef1) gets ahead of
generator 2 emf (Ef2) there by a resultant emf (Ec) appears.
Due to this resultant emf, Ec a circulating current Ic (fig
i) flows which lags Ec by almost 90. (as the value of resistance is too
small compared to the reactance of the machine). This current flows out of gen 1
nearly in phase with it’s emf Ef1 and enters gen 2 in near phase
opposition with Ef2. Thus Gen 1 produces power (=Ef1Ic)
as a generator and supplies it to Gen 2 which acts as a motor. This would thus retard the faster machine and
accelerates the slower one, finally leading to auto equalization of speed.
It is necessary that the machines impedance shouldn’t be
purely resistive. If they are purely resistive, then the circulating current
would be in phase with Ec (fig ii) and thereby both will act as generator. There would be no tendency of auto equalization of speed. It implies that there would be frequency mismatch leading to power surges and harmonics.
ON LOAD:
The load current I
L
= I
a1 + I
a2 (can be seen in the circuit beside). Increasing the driving torque would result a
change in the amount of load shared, the currents I
a1 and I
a2
and respective power factors. Howsoever, the load current I
L remains
constant. First, we’ll see how load sharing varies.
On load operation depends upon the speed-load characteristics of the
alternator. Generally these characteristics are not linear. Hence a governor
mechanism is used to make them linear as in the figure beside.
If we increase the
driving torque of Gen1, speed increases and the speed-load curve shifts upwards
indicating the increase in speed. Obviously decreasing the driving torque would
shift the characteristics downwards.
Consider the two generators are supplying to a
load PL (=P1+P2 initially). Now if we increase
the driving torque of gen1. It’s speed-load characteristics shift upwards. In
order to maintain the frequency (as the load is constant) the driving torque of
gen2 should be decreased. Thus the dotted lines in the figure indicate the
speed load characteristics of both the generators and the line2 indicates the
frequency of the constant load. Thus the load shared by gen1 increases to P1’
and the load of gen 2 decreases to P2’ but to the end the sums of
loads shared by both the generators would be constant and equal to the total
load PL.
Now let us see how the currents and power factors of each generator is
effected.
At first assume that Ef1= Ef2
and therefore Ia1=Ia2 and the load shared will be equal.
Now increase the driving torque of
gen 1 which increases the speed and frequency and thereby increasing the power
angle
δ to
δ1 and the power
increases to P
1’
.
The driving
torque of gen2 is now decreases in order to supply to the load at constant
frequency. Ef2 decreases and power angle also decreases to δ2 and the power decreases to P2’.
More over, this
change in the emfs will lead to a resultant emf Ec. Hence, a
circulating current flows which lags Ec almost 90.. This
current adds up to Ia1 and hence current through gen 1 increases
(indicating that the load shared by this gen has increased). The power factor
angle decreases thereby improving the power factor. The current Ic reduces
the current from gen 2 and there by indicating that the load shared by this gen
is reduced. The power factor angle increases and thereby decreasing the
power factor.
Thus we can conclude that, by increasing the driving torque
on load increases the load shared, current and also improves the power factor.